x^2+6x-4=2(3x-2)

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Solution for x^2+6x-4=2(3x-2) equation: 


Simplifying
x2 + 6x + -4 = 2(3x + -2)

Reorder the terms:
-4 + 6x + x2 = 2(3x + -2)

Reorder the terms:
-4 + 6x + x2 = 2(-2 + 3x)
-4 + 6x + x2 = (-2 * 2 + 3x * 2)
-4 + 6x + x2 = (-4 + 6x)

Add '4' to each side of the equation.
-4 + 6x + 4 + x2 = -4 + 4 + 6x

Reorder the terms:
-4 + 4 + 6x + x2 = -4 + 4 + 6x

Combine like terms: -4 + 4 = 0
0 + 6x + x2 = -4 + 4 + 6x
6x + x2 = -4 + 4 + 6x

Combine like terms: -4 + 4 = 0
6x + x2 = 0 + 6x
6x + x2 = 6x

Add '-6x' to each side of the equation.
6x + -6x + x2 = 6x + -6x

Combine like terms: 6x + -6x = 0
0 + x2 = 6x + -6x
x2 = 6x + -6x

Combine like terms: 6x + -6x = 0
x2 = 0

Solving
x2 = 0

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Simplifying
x2 = 0

Take the square root of each side:
x = {0}

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